For the purposes of classifying “single-bonded” root systems, we would like to consider the following (finite) incidence structure, known as generalised quadrangle
A pair
with
a set (elements of
are referred to as points) and
(elements of
are referred to as lines) is called a generalised quadrangle provided the following holds:
- the lines are of size at least 2
- for every point there is at least one line containing it
- for every point
and every line
there exists unique line
such that
The 3rd axiom implies that two lines intersect in a most one point, and so indeed can be visualised as such. This permits one to talk about collinearity of points: two points are collinear iff there exists a line containing them both. Also, note that it implies that in there are no “triangles”, i.e. triples of lines each two of which intersect, so that there are 3 non-collinear intersection points in total.
Examples
- a “line”
i.e. there is just one line on all the points
- a “claw”, i.e.
such that there exists
such that
for all
(and so any
is on just one line)
- a complete bipartite graph, i.e.
with
being the set of vertices of a complete bipartite graph and
being the set of its edges (so in particular every line contains just 2 points)
- a “grid”, i.e.
with
being two sets of parallel lines in
and
being their pairwise intersections
- for
let
with
being the set
of unordered pairs of elements of
b and
the set of partitions of
into three pairs; in particular
Note that the 3rd and the 4th examples are dual to each other in the following sense.
In the points are the lines of
and the lines are the sets of lines collinear to a point
for each
Let
be a generalised quadrangle. Then its dual, the incidence system
is also a generalised quadrangle, provided that it is neither a “line” nor a “claw”.
We have to exclude “lines” and “claws” as their duals have lines of size 1.
To emphasise the roles of points and lines as dual to each other, we say that and
are incident if
It is an interesting exercise to show that the 5th example is self-dual, i.e. there exists a bijection preserving the incidence point-line relation.
Regularity
The 3rd axiom implies that for any two skew (i.e. non-intersecting) lines there is a bijection
between the sets of points incident to them. This means that any two lines
without
must intersect. One can show that more than two different cardinalities are only possible for a “claw”, as follows:
Three lines with three different cardinalities must have a common intersection point, say
A line
that is not on
can intersect at most one of the three lines, say
Therefore there are bijections
and
and
is a bijection between points on
and points on
contradiction proving the claim.
Similarly, one can show that two different cardinalities are only possible for a “grid” or a “claw”. Indeed, let be two skew lines, and
a line of a different cardinality. Then every line
that joins a point on
to a point on
must have the same cardinality as
On the other hand, every line of a cardinality different from the one of
intersects both
and
In particular these lines do not intersect. Similarly, the lines with the same cardinality as
intersect
and
It follows that we have a “grid”.
It is also not hard to see that when all the lines are of size 2 we have the complete bipartite graph example.
From now on let us assume that all the lines has the same cardinality and that
has the dual. Looking at the dual, we either encounter one of the “easy” cases as above, or derive that all the dual lines must have the same cardinality
Such
are called regular.